0.5x^2=15x

Solution for 0.5x^2=15x equation:

0.5x^2=15x

We move all terms to the left:

0.5x^2-(15x)=0

a = 0.5; b = -15; c = 0;
Δ = b2-4ac
Δ = -152-4·0.5·0
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{225}=15$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-15}{2*0.5}=\frac{0}{1}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+15}{2*0.5}=\frac{30}{1}
=30
$